The Solar Map
That is Giza
Further Explorations at Giza and Our Solar System
For a background to this new website go here. http://donbarone.selfip.net/curious.htm
To which we can add this.
The total distance of the 8 planets from The Sun added together is 6,298,078,180 miles:
According to me the distance from the
south side of G2 to the south line of what we refer to as The
Giza Rectangle should be and is in fact 629.81 cubits. This would
represent if correct that each cubit of this 629.81 would
represent 10,000,000 miles. The perimeter we find is also to be
included as it totals 6298.078180 cubits and thus the scale here
would be 1 cubit is equal to 1,000,000 miles and the distance
from the south side of G2 to the south base of "The Giza
Rectangle" is precisely 1/10 th of the perimeter.
As a check let us calculate the distances of the sides of "The Giza Rectangle". According to me the distance from the west side of G1 to the west side of "The Giza Rectangle" should be 1/2 the diagonal of a square measuring 440 cubits or 1/2 of 622.254 cubits times Pi which equals 311.127 times Pi or 977.434 cubits. This 977.434 when added to base of G1 which is 440 cubits gives us a distance of 1417.434. If my distance of 6298.078180 cubits for the perimeter is correct then two times 1417.434 would reveal the total distance for the two long sides. So 1417.434 times 2 is equal to 2834.868 cubits. This would leave us for the two long sides a distance of 6298.078180 - 2834.868 or 3463.210 cubits and divided by two would give us the length of the long side as 3463.210 / 2 = 1731.605 cubits. 1731.605 subtract base or side of G1 of 440 cubits leaves us 1291.605 cubits. If like 977.434 this distance also represents a circumference then let us divide 1291.605 cubits by Pi and we get 411.130 and the longest of the four sides of G2 is in fact 411.14 or checking to within 1/100th of a cubit.
I think this proves beyond a shadow of a doubt that The Solar System is defined and shown at Giza. There is tons more but this I think makes it quite clear.
Since some people like inches so much
what does 6298.078180 cubits equal in inches ? If we use 20.62 we
get 6298.078180 x 20.62 = 129866.37 inches. If we use
20.618033988 or 20.Phi we get 129853.98998 inches. If we divide
by Pi we get 41333.8088 inches
The semi major axis of Ceres, technically the middle planet of 9 if we include it as a planet, is 413,690,604 kilometers from The Sun and this checks for 41333.8088 to a degree of accuracy of 99.91 %, however the more interesting thing is that it appears that the total orbital distance traveled by Ceres which is approximately 1,299,647,362 kilometers appears to correspond to the perimeter of The Giza Plateau AND the total distance that the 8 planets are away from The Sun to a scale of 1 inch (at Giza and on the perimeter) is equal to 100,000 kilometers in our solar system.
413690604 IS NOT THE DIAMETER as I had calculated but is of course the radius of the orbital distance so it is not 100,000 miles per inch but 50,000 miles as according to this ellipse calculator we get 2,595,200,000 as a perimeter or ellipse distance which when divided by 2 gives us 1,297,600,000 which checks to 129853.98998 inches for 99.93% accuracy.
According to a source Ceres's approximate orbit = 2,596,100,000 Km. If true half of this is 129,805,000 kilometers. If we use 20.618033988 or 20.Phi we get 20.618033988 x 6298.078180 or 129853.98998 inches. 129805000 / 129854 = 999.62 or 99.96% accuracy. So 1 inch on the perimeter at Giza is equal to 2000 kilometers of Ceres' orbital total distance to a degree of accuracy of 99.96%
More Mars - Earth relationships
Sq rt of 3 =
Phi = 1.6180339887498948482045868343656
Sq rt of 3 / Phi = 1.07046627
440.00 (base of Great Pyramid in cubits) / 1.07046627 = 411.035838 cubits
Base of G2 in cubits = 411.04
Accuracy = basically 100%
Mercury 57,909,100 (semi major axis distance from The Sun in kilometers)
Venus 108,208,930 (semi major axis distance from The Sun in kilometers)
411.04 / 220 (1/2 base G1) = 1.868364
108,208,930 / 57,909,100 = 1.8685998
Accuracy = 99.987 %
Nick L and I were working on a variety
of things we noted (honestly can't remember whether it was him or
I) that our solar system seems to be a simplified 9 by 11 right
angled triangle. That is that the first three planets in our
solar system can be found using this most simple of devices. The
sides are of course 9 and 11 and the contained angles are 39.2894
degrees and 50.7106 degrees. Observe a few simple diagrams.
In the first one I simply draw our right-angled 9 by 11 triangle.
and now label it.
Now let's draw in The Sun and Earth ...
... and now to add Mercury corresponding to 5.5 grid units or 440 cubits in our diagram
... and finally let us add Venus.
Please note that the hypotenuse is
simply the square root of 9 squared + 11 squared or square root
of 202 or 14.2126704 grid units.
Now let us check the calculations.
We have assigned Mercury 5.5 grid units and this equals 57,909,100 kilometers. Earth we have as 14.2126704 grid units and this divided by5.5 grid units of Mercury gives us 2.584121892 Mercury units or 2.584121892 x 57,909,100 or 149,644,173 kilometers. Let's check to what it should be.
Distance to Earth from The Sun is equal to 149,598,261 kilometers (semi-major axis). This gives us a degree of accuracy of 149598261 / 149,644,173 or 99.97 %
Venus appears to be at co-ordinates 6.5 by about 7.91 approx. This yields a distance from The Sun to Venus of about 6.5 squared + 7.91 squared or 104.8181. Square root of this is 10.2381. divide this by Mercury or 5.5 units and we get 1.86147. 1.86147 x 57,909,100 = 107,795,906 kilometers.
Perihelion of Venus = 107,477,000 km / 107,795,906 = 99.70
Semi-major axis 107,795,906 / 108,200,000 = 99.63
Not as accurate as usual but definitely a nice simple way of graphically drawing our solar system without using circles. And just a thought as this might be a possible reason why there are no 90 degree angles at Giza.
Interestingly if we include Pluto then
the total distance to all the planets added together equals
9,948,012,563. I thought perhaps it should be 10,000,000,000 even
but then I decided to divide this total by the distance that
Earth is from The Sun which is 92,955,817 miles. This is what it
9,948,012,563 / 92,955,817 = 107.01872
Now probably only because I have worked on Giza for so long but I immediately recognized this number. If we divide base G1 by base G2 we get
440 / 411.04 = 1.0704554
Sq root of 3 / Phi = 1.07046627
440 / 411.14 (south base of G2) = 1.07019507 (439.88 / 411.04 = 1.0701635 )
107.01872 / 1.07019507 = 99.9993
Conclusion: The ratio of G1 to G2 is equal to the ratio of the total distances involved in all the planet distances compared to The Earth alone to a ratio of 1 to 100.
Fact: The diameter of Earth = 7,926.3352
Fact: Distance from center of east side G1 to center of west side of G3 or more commonly known as The Chase Line is 2000.00 cubits + or - 0.5 cubits
Circumference of a circle with diameter of 2000 cubits is 6283.1853072 cubits
Square root of 6283.1853072 cubits = 79.266546
CONCLUSION: The Chase Line when used as a diameter and following the steps outlined above yields the diameter of The Earth in miles in a ratio of 1 cubit = 100 kilometers to a degree of accuracy of 99.996 %
I think most people are missing the
significance of what is being displayed at Giza. What we have is
a map of The Solar System but it is being done and shown WITHOUT
CIRCLES !. It is very significant that the ratio
between the semi major distances from The Sun of Mercury compared
to Venus is approximately (1/2 the v3 + 1 ) to 1 or 0.8660254 + 1
or 1.8660254 The actual is 108208930 /
57909100 = 1.8686. (accuracy only 99.86%). It is for this reason
that the north - south distance is not 1732.05 but is in fact
1732.28 cubits. The slight variation from the square roots of 2
and 3 allow the map to work.
Below we are finding the center of the north-south and east-west lines.
Next I am going to draw the three inner planets on this diagram in one of the more logical ways. We then get this diagram below.
Now let's draw the lines which will correspond to the semi major distances.
Next let's do some calculations. There is and will always be a constant argument over what exactly is the correct distances at Giza. Many different ones have been used but for this exercise I am going to use 1732.28 cubits for the north-south distance. One half of this is 1732.28 / 2 = 866.14. We have our first distance. We are going to use 866.14 cubits to represent the distance from The Sun to Mercury or 57,909,100 kilometers.
Another thing that has gone almost completely unnoticed on this board is that the ratio between the semi major axis of Earth and of Mercury is precisely the ratio of 31 / 12 or 2.583333333. This would make the distance to Earth at Giza 2.583333 x 866.14 or 2237.52833 cubits. Venus is 1.8686 x 866.14 or 1618.469 (very close to Phi x 1000).
In order for the diagonal to equal 2237.52833 we need an east-west measurement of v2237.52833² - 1732.28² = x
x = v5006533.0275525889 - 3000793.9984
x = v2005739.0291525889
x = 1416.241162074
This gives us this diagram below.
However in order to get 1618.469 we also need the east-west distance to equal 1414.40 cubits as shown below.
On the surface this seems impossible until we remember that the pyramids are not 90 degrees and G3 is especially offset from 90 degrees by almost 16.6 minutes. Once we see this then we do in fact have FOUR different measurements east-west depending on which corner of G3 we use.
A possibility ?
Just a note:
Distance of semi major axis of Mars = 141634790
Checks to our 141634790 / 1416.24 distance to 9.99923816e-6 or about 99.99 % after divided by 100,000.
Okay here are the "circular" orbits of the three inner planets but ...
... there is one of the inner planets
missing. Where is Mars ?
Well after trying a variety of experiments I think I have figured it out.
However we have to change the scale. Where as in the first series we had Mercury equaling 866.14 cubits this time we will set The Earth at this distance. But first we need the ratio of Mars and Earth and we get: 227,939,100 / 149,598,261 = 1.5236748 So using this scale the distance to Mars would equal 866.14 x 1.5236748 or 1319.7157 cubits. Now interesting this just happens to be 3 quarters (3/4) of the perimeter of G1 (440 x 3 = 1320). However perhaps we need to look beyond Giza to find Mars. Mars is called The Red Planet and there is of course The Red Pyramid. Could they be related ? Well interestingly when we divide 1319.7157 x Pi we get ... 420.0786 and this checks to the assumed base of The Red Pyramid of 420 cubits to a degree of accuracy of 99.98 %
Clive Ross was the first (and only)
person ever to see the ratio 6/3.14 and tie it into volume of a
sphere at Giza. What he failed
to see was that same ratio is found in the distance of the planets Mars and Earth from The Sun in their semi major axis'. For example
if we allow Earth to equal 6 then Mars is 6 + 3.14 or 9.14. (149598261 / 6 = 24933043.5 x 9.14 = 227888017.59. The correct figure is
227939100) But what also is amazing is that same ratio 6 / 3.14 is also the ratio of the cubit to the meter.
(39.37 inches / 20.618034 inches = 1.9049341. I honestly do not understand why the fact that two measurements on Earth (meter and cubit)
that correspond to two planets in our solar system (Earth and Mars) and also solves for the volume of a sphere continues to be ignored by the masses.
Here is an image based on the image that Clive discovered that show these various ratios.
In this diagram below by Clive Ross we are shown a certain ratio:
Is it showing us the ratio of the meter
to the cubit ?
Is it showing us the ratio of Earth's semi major axis and the difference of Earth and Mars from The Sun
Is it showing us the ratio of the volume of a sphere to that of a cube ?
Is it showing us the ratio of all of them ?
Is it showing us another nice safe co-incidence ? Because if it is a co-incidence we don't have to think about it.
And now another exercise in mathematics and our solar system and Giza.
Let us take 880 units, call them miles for now. Now let's figure out how many kilometers that is. 880 x 1.609344 = 1416.22272 okay now let's keep the miles going and let's assume this is also miles we then get (converting to kilometers) 1416.22272 x 1.609344 = 2279.18953709568.
Hmmm ... okay now let's multiply by 100,000 and we get 227,918,954 kilometers. Now interestingly the distance of Mars from The Sun on it's semi major axis is 227,939,100. This little exercise checks to a degree of accuracy of 99.991 %
But more importantly I think it shows that the perimeter of The Great Pyramid as well as showing Mercury and Earth also shows us Mars for if we assume that 1760 (cubits and perimeter of The Great Pyramid) are miles then in kilometers we have 2832.44544 and this gives us a ratio of 1 kilometer = 1 mile for Mars' major axis which is 455,878,300 for 2832.44544 x 1.609344 = 4558.37907
4558.37907 / 455,878,300 = 99.991 % accuracy
So now we have shown that The Great Pyramid is Mercury, Earth and now also brilliantly and cleverly Mars as well.
I mean really just how clever were these designers ? Or ... are they just copying ... The Creator ?
Lest we question whether the pyramids were really meant to represent the planets I offer this as a testimony to the builders and their work.
And this ....
And interestingly 641.50 x 2.7 = 1732.05 or v3 x 1000
and 641.50 x 5.4 = 3464.1 = (v3 x 1000) x 2
Combine this with the fact that 280 (height of G1 in cubits) x 5.4 = 1512.00 cubits and we get this diagram.
Just a reminder that The Giza Plateau is a reproduction of The Great Pyramid on a scale of 1 to 5.4.
Mars radius = 3,396.2
Mercury radius = 2,439.7
Ratio = 1.3920564003770955445341640365619 or 0.71836169836876509039514751781403
G2 + G3 = 612.50 / G1 = 440 = 1.3920454545454545454545454545455 or 0.71836734693877551020408163265306
1.3920454545454545454545454545455 / 1.3920564003770955445341640365619 = 0.99999213693379231333415421513883
or 99.9992 %
So it checks for 8/10,000ths of a percent.
First the ratios
Mercury = 57,909,100 km
Venus = 108,208,930 km or 1.8686 x Mercury
Earth = 149,598,261 km or 2.5833 x Mercury
Mars = 227,939,100 km or 3.93615 x Mercury
It is my contention that by simply using a 9 by 11 grid drawn within a triangle or rectangle the solar system can be plotted and this is
what is being shown to us at Giza.
The building blocks as posted earlier on this thread.
Now let us move the playing field to The Giza Plateau.
But first the ratios again.
Mercury will be 440.00 cubits and be the base of The Great Pyramid
Venus will be 822.28 cubits and will be twice the south base of G2
Earth will be shown later in the diagrams
Mars will be the total north-south distance at Giza and will be about 1732.00 cubits
Now some diagrams:
Here is Venus plotted:
The solid lime green line will equal the semi major axis of Venus to a degree of accuracy of 99.988 %
( 822.28 / 440 = 1.86882 x 57,909,100 = 108,221,579
108,08,930 / 108,221,579 = 99.988 % )
Now let us turn the Giza Rectangle to show our original rectangle. We do this by turning it counter clockwise 50.71° which is
the large angle in a 9 by 11 triangle. Here is what we have after doing this..
When we do this we get earth as being the hypotenuse on a 9 by 11 triangle of 14.2167
Our triangle is 9 by 11 and each unit is 80 units for example the triangle is 9 x 80 or 720 (which is base of G1 plus height
or 440 + 280) and 11 x 80 or 880 (which is twice base of G1) This leads to this clever diagram.
and righting it gives us this:
and drawing in the missing line gives us this.
Earth = 1137.0136 on our diagram and should be 149598261 / 57909100 = 2.58333 x 440 = 1136.66
Accuracy = 1136.66 / 1137.01 = 99.97 %
So what does all of this prove. Well to me the fact that you can design and build a scale model of the solar system using just a 9 by 11 grid
and the bases and heights of the pyramids as left to us by the ancient builders should be a cause for celebration. Basically knowing the sizes
of the pyramids and having a straightedge and ruler one can draw our solar system, The more amazing thing is that it is there in plain sight
for anyone to see at The Giza Plateau all one has to do is open one's eyes. But I am unsure what the most amazing thing is. Is it the fact
that the solar system seems to follow such a simple plan or is it the fact that ancient man knew about it and left it to us to re-discover
at Giza. It is tragic that more people don't seem to get it and that it is not taught in school. Even a primary class, if they knew The
Pythagorean Theorem, could understand it and draw their solar system to scale.
So simple yet so hard for some to see.
A corrected image ...
Here are some new updated distance
listings from NASA on their site currently:
All semi major axis'
Mercury = 57,909,227 kilometers
Venus = 108,209,475 kilometers
Earth = 149,598,262 kilometers
Mars = 227,943,824 kilometers
oes this help or hinder our earlier
Well one of the ratios was that the distance from The Sun to The Earth equaled a meter while the difference from Earth to Mars equaled a cubit. Do these new measurement help our accuracy ? Observe:
Difference of 227,943,824 - 149,598,262 = 78,345,562 kilometers or 1 cubit
Earth's distance of 149,598,262 then equals a meter.
149,598,262 / 78,345,562 = 1.9094669587
As you know I claim that a cubit is 20.618034 inches
A meter has 39.37 inches so 39.37 / 1.9094669587 = 20.6183196
Accuracy = 20.618034 / 20.6183196 = 99.9986 %
Venus / Mercury = 108,209,475 / 57,909,227 = 1.868605
220 x 1.868605 = 411.0931
North side of G2 = 411.04 cubits
South side of G2 = 411.14 cubits
Average = 411.09 cubits
Ratio 411.09 / 411.0931 = 99.9993 %
We had noted that 100 digits / 28 equal
3.5714285714 cubits and had also noted that the the overall
distance from north side of G1 to south side of G3 was 35,713.5
inches. Obviously a possible connection.
Returning to our solar system again we have:
Mercury at 57,909,100 kilometers from The Sun
Ceres is 413,690,604 kilometers from The Sun although this number varies quite a bit depending on where you check.
Let's double the number of cubits to (100/28) x 2 = 7.142857143
If we let distance to Mercury (semi major axis) = 1 and 57,909,100 we can calculate for Ceres a value of 7.142857143 x 57,909,100 and get 413,636,429 kilometers.
413636429 / 413690604 = 99.987 %
Below find a comprehensive diagram of
all distances involved in our solar system and note the
NOTE 1) The difference in the semi major axis' of Earth and Venus is 149597870.7 - 108208930 = 41,388,940.7
Semi major axis of Ceres is 413,781,191 kilometers
413,781,191 / 41,388,940.7 = 9.9974 or 10 to an accuracy of obviously 99.97 %
NOTE 2) The difference in the semi major axis' of Mercury and Venus is 50,299,880 kilometers.
Semi major axis of Ceres is 413,781,191 kilometers
413,781,191 / 50,299,880 = 8.2263
2 x base of G2 is 2 x 411.14 = 822.28
822.28 / 8.2263 = 99.957 100 accurate to obviously 99.957 %
NOTE 3) At Giza we have G1 @ 440 cubits
G2 + G3 = 411.04 + 201.46 = 612.50
Ratio is 612.50 / 440 = 1.3920454545454545454545454545455
Now we have already determined that this ratio is EXACTLY THE RATIO BETWEEN THE DIAMETERS OF MARS AND MERCURY being 6792.4 and 4879.4 as 4879.4 x 1.39204545 = 6792.34656873 accuracy this time of 99.999 % !!!
However we are not quite done or at least The Creator or the builders of Giza are not quite done because this ratio also shows us another relationship.
If we allow Earth to equal G2 + G3 or 612.50 cubits then G1 @ 440 cubits would equal 149597870.7 / 1.3920454545454545454545454545455 = 107,466,225. Now Perihelion (closest approach to The Sun) of Venus is 107,476,259 km ...
This checks to 107,476,259 / 107,466,225 = 99.99 %
Difference in semi major axis' of Venus and Mars is 227939100 -
108208930 = 119730170
Difference in semi major axis' of Mercury and Venus is 108208930 - 57909050 = 50,299,880
Ratio of these two = 119730170 / 50,299,880 = 2.38032715
Earth astronomical unit again is 149,597,870.
Divide 149,597,870 x 2.38032715 = 356091873.
Divide by 1,000,000 = 356.09
Back to G1 and we have v220² + 280²
v48400 + 78400
Accuracy = 356.0898763 / 356.091873 = 99.9994 %
To be continued ... July 11th, 2013